Diketahui persamaan kuadrat x²+3x-10 memiliki akar-akar persamaan padan q. Jika p>q hitunglah nilai 2p - q
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x² + 3x - 10 = 0
5 + (-2) = 3
5 × (-2) = -10
(x + 5)(x - 2) = 0
x1(q) = -5 x2(p) = 2
2p - q
= 2(2) - (-5)
= 4 + 5
= 9
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